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7x^2+7x-4=-4+6x
We move all terms to the left:
7x^2+7x-4-(-4+6x)=0
We add all the numbers together, and all the variables
7x^2+7x-(6x-4)-4=0
We get rid of parentheses
7x^2+7x-6x+4-4=0
We add all the numbers together, and all the variables
7x^2+x=0
a = 7; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·7·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*7}=\frac{-2}{14} =-1/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*7}=\frac{0}{14} =0 $
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